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Proof step 3 from proof ls-mult-2pot (previous step)

i0 = i1 + i, 0 < j, 0 ≤ i, 0 ≤ i0 ⊦ j * 2 ^ i < 2 ^ i0 ↔ j < 2 ^ i1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
0 < j, 0 ≤ i, 0 ≤ i1 + i ⊦ j * 2 ^ i < 2 ^ (i1 + i) ↔ j < 2 ^ i1

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs