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Proof step 1 from proof ls-pos-01 (conclusion)

⊦ i ≤ i0 ∧ 0 ≤ i ∧ 0 ≤ j → i ^ j ≤ i0 ^ j

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ls-pos-02: ⊦ i ≤ i0 ∧ 0 ≤ i ∧ 0 ≤ j → ¬ i0 ^ j < i ^ j;%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs