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Proof step 3 from proof ls-pos-02 (previous step)

i0 ^ j < i ^ j ∧ i ≤ i0 ∧ 0 ≤ i0 ∧ 0 ≤ i ∧ 0 ≤ j, ∀ j0, i0, i. i→n(j0) < i→n(j) → i0 ^ j0 < i ^ j0 ∧ i ≤ i0 ∧ 0 ≤ i0 ∧ 0 ≤ i ∧ 0 ≤ j0 → false ⊦ false

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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