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Proof step 2 from proof ls-pos-03 (previous step)

0 ≤ i, 0 ≤ i0, 0 < j ⊦ i ^ j < i0 ^ j ↔ i < i0

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

Additional information

Used simplifier rules: le-pos-01: ⊦ 0 ≤ i ∧ 0 ≤ i0 ∧ 0 < j → (i ^ j ≤ i0 ^ j ↔ i ≤ i0);%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs%lels-03: ⊦ i < j → (¬ ¬ j ≤ i ↔ false); from specification int-abs