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Proof step 1 from proof ls-pos-2pot (conclusion)

⊦ 0 ≤ j → (2 ^ j < 2 ^ j0 ↔ j < j0)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ls-pos: ⊦ 1 < i ∧ 0 ≤ j → (i ^ j < i ^ j0 ↔ j < j0);