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Proof step 11 from proof ls-pos (previous step)

j < j0, 0 < i, 1 < i, 0 ≤ j, i ^ j0 ≤ i ^ j, 0 < j0 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-pot inst: name: le-pos seq: ⊦ 1 < i ∧ 0 ≤ j → (i ^ j ≤ i ^ j0 ↔ j ≤ j0) subst: [j0, j, i] → [j, j0, i] flags: rewrite, current

Additional information

Used simplifier rules: lenls: ⊦ i ≤ j → ¬ j < i; from specification int-abs%numlelsdel-01: i0 ≠ 0, i0 ≤ i ⊦ (* i) < j → (* i0) < j; from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1 Used terms: j, j0, i