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Proof step 3 from proof ls-pos (previous step)

i ^ j < i ^ j0, 0 < i, 1 < i, 0 ≤ j ⊦ j < j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i ^ j < i ^ j0, 0 < i, 1 < i, 0 ≤ j, j0 ≤ j ⊦

Rule argument

Additional information

Used simplifier rules: lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs