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Proof step 1 from proof minus-one-odd (conclusion)

⊦ 0 < j ∧ j % 2 = 1 → ~1 ^ j = ~1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
j % 2 = 1, 0 < j ⊦ ~1 ^ j = ~1

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs