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Proof step 2 from proof minus-square (previous step)

0 ≤ j ⊦ ~ i ^ (2 * j) = i ^ (2 * j)

User applied rule induction

And obtained the following new goals

Proof step 3:
0 ≤ j, ∀ j0, i. i→n(j0) < i→n(j) → 0 ≤ j0 → ~ i ^ (2 * j0) = i ^ (2 * j0) ⊦ ~ i ^ (2 * j) = i ^ (2 * j)

Rule argument

indvar: i→n(j) wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: i→n(j)