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Proof step 15 from proof mod-two-ge-01 (previous step)

2 ^ (i0 + j) = i1 + 1, 0 ≤ j, 0 < i0, 0 < i0 + j ⊦ 2 ^ (i0 + j) = 2 ^ j * (i1 / 2 ^ j + 1), 2 ^ (i0 + j) = 2 ^ j * 2 ^ i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information