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Proof step 8 from proof mod-two-ge-01 (previous step)

¬(0 < 1 ∧ 1 < 2 ^ j ∧ 0 < 2 ^ (i - j)), j < i, 0 ≤ j, 0 < i ⊦ 2 ^ j * 2 ^ (i - j) = 2 ^ j * ((2 ^ j * 2 ^ (i - j) - 1) / 2 ^ j + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information