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Proof step 6 from proof mod2-2pot (previous step)

0 ≤ i0 ⊦ (j % (2 ^ i0 * 2)) % 2 = j % 2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ i * j = j * i
Proof step 8:
0 ≤ i0 ⊦ (j % (2 * 2 ^ i0)) % 2 = j % 2

Rule argument

spec: int-mult inst: name: commutativity seq: ⊦ i * j = j * i subst: [j, i] → [2, 2 ^ i0] flags: rewrite

Additional information

Used terms: 2, 2 ^ i0