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Proof step 4 from proof notneg (previous step)

1 < i ∧ 0 < j → ¬ i ^ j ≤ 1, i ^ j < j, i ^ j < i, i ^ j < 0, 0 ≤ j, 0 ≤ i ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 ≤ i, 0 ≤ j, i ^ j < 0, i ^ j < i, i ^ j < j, i ^ j ≤ 1 ⊦ 1 < i ∧ 0 < j

Rule argument

Additional information

Used simplifier rules: trans: ⊦ i < j ∧ j < j0 → i < j0; (forward) from specification int-basic1%lf-01: ⊦ i < j ∧ j < i0 → i +1 < i0; (forward) from specification int-basic1%numlsf-02: ⊦ (* i) < j → i + 1 ≤ j; (forward) from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs