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Proof step 3 from proof notone (previous step)

2 ≤ i, i ^ j < i, i ^ j ≤ 1, 0 < j, 1 < i, ∀ j0, i. i→n(j0) < i→n(j) → true → 1 < i ∧ 0 < j0 → ¬ i ^ j0 ≤ 1 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ 0 < i → j ^ i = j ^ i -1 * j
Proof step 5:
0 < j, 2 ≤ i, i ^ j -1 * i < i, i ^ j -1 * i ≤ 1, 0 < j, 1 < i, ∀ j0, i. i→n(j0) < i→n(j) → true → 1 < i ∧ 0 < j0 → ¬ i ^ j0 ≤ 1 ⊦

Rule argument

spec: int-pot inst: name: Pot-pos seq: ⊦ 0 < i → j ^ i = j ^ i -1 * j subst: [i, j] → [j, i] flags: rewrite, current

Additional information

Used terms: j, i