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Proof step 8 from proof pot-add-min (previous step)

¬(0 ≤ j - min(j, j0) ∧ 0 ≤ min(j, j0)), 0 ≤ j, 0 ≤ j0 ⊦ i * 10 ^ j + i0 * 10 ^ j0 = i * 10 ^ (j - min(j, j0)) * 10 ^ min(j, j0) + (i0 * 10 ^ (j0 - min(j, j0))) * 10 ^ min(j, j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: Pot-neg: ⊦ i < 0 → j ^ i = 1 / j ^ abs(i);%zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%zero-gels-03: ⊦ i < 0 ∧ 0 ≤ j → i ≤ j; from specification int-abs%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%abs-08: ⊦ i < 0 → abs(i) = ~ i; from specification int-abs%min-c: ⊦ min(i, j) = min(j, i); from specification int-min%min-a: ⊦ min(i, min(j, j0)) = min(min(i, j), j0); from specification int-min%min-03: ⊦ ¬ i < min(i, j); from specification int-min%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-zero-rev: ⊦ 0 + i = i; from specification int-basic2%sub-le-01: ⊦ i ≤ j - i0 ↔ i + i0 ≤ j; from specification int-abs