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Proof step 3 from proof pot-div (previous step)

j = i0 + j0, j0 ≤ j, 0 ≤ j0, 0 ≤ j, 0 < i ⊦ i ^ j / i ^ j0 = i ^ i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
0 ≤ j0, 0 < i, 0 ≤ i0 + j0, 0 ≤ i0 ⊦ i ^ (i0 + j0) / i ^ j0 = i ^ i0

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%lep: ⊦ i ≤ i + j ↔ 0 ≤ j; from specification int-abs