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Proof step 8 from proof pot-div3-nls (previous step)

(j ^ (i - 1) * j) / 3 < j, 2 ≤ j, 2 < i, 0 ≤ j, 0 < j, 0 < i, 1 < i, j ^ (i - 1) < j * j ⊦

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 9:
i = i0 + 1, (j ^ i0 * j) / 3 < j, 2 ≤ j, 2 < i, 0 ≤ j, 0 < j, 0 < i, 1 < i, j ^ i0 < j * j ⊦

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [i, 1, i0] flags:

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: i, 1, i0