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Proof step 1 from proof pot-eq-sub (conclusion)

⊦ 0 < j ∧ 0 ≤ j0 ∧ j0 ≤ j1 → (i * j ^ j0 = i0 * j ^ j1 ↔ i = i0 * j ^ (j1 - j0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
j0 ≤ j1, 0 < j, 0 ≤ j0, 0 ≤ j1 ⊦ i * j ^ j0 = i0 * j ^ j1 ↔ i = i0 * j ^ (j1 - j0)

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs