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Proof step 18 from proof pot-mod-add-zero (previous step)

j ≠ 0, ∃ j0. i = j0 * j, 0 ≤ j, 0 ≤ i1 ⊦ (i + i0 * j ^ i1 * j) % j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
0 ≤ i1, 0 < j ⊦ (j0 * j + i0 * j ^ i1 * j) % j = 0, j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs