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Proof step 2 from proof pot-mod-zero (previous step)

j0 ≤ j1, 0 < j, 0 ≤ j0, 0 ≤ j1 ⊦ j ^ j1 % j ^ j0 = 0

User applied rule cut formula

And obtained the following new goals

Proof step 3:
j ^ j1 = j ^ (j0 + (j1 - j0)), j0 ≤ j1, 0 < j, 0 ≤ j0, 0 ≤ j1 ⊦ j ^ j1 % j ^ j0 = 0

Rule argument

fma: j ^ j1 = j ^ (j0 + (j1 - j0))

Additional information

Used simplifier rules: Sub-def: ⊦ i + (j - i) = j; from specification int-abs%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used formulas: j ^ j1 = j ^ (j0 + (j1 - j0))