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Proof step 2 from proof pot-pot (previous step)

0 ≤ i ∧ 0 ≤ j ∧ 0 ≤ j0, ∀ j1, i, j. i→n(j1) < i→n(j0) → 0 ≤ i ∧ 0 ≤ j ∧ 0 ≤ j1 → (i ^ j) ^ j1 = i ^ (j * j1) ⊦ (i ^ j) ^ j0 = i ^ (j * j0)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: pot-pot-03: ⊦ 0 ≤ j ∧ 0 ≤ j0 → (i ^ (j * j0) ≠ (i ^ j) ^ j0 ↔ false);%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult