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Proof step 3 from proof pot-square-est-01 (
previous step
)
4 ^ i ≤ i * i ∧ 0 ≤ i, ∀ i0. i→n(i0) < i→n(i) → 4 ^ i0 ≤ i0 * i0 ∧ 0 ≤ i0 → false ⊦ false
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 4
:
4 ^ i ≤ i * i, 0 ≤ i, ∀ i0. i→n(i0) < i→n(i) → 4 ^ i0 ≤ i0 * i0 ∧ 0 ≤ i0 → false ⊦
Rule argument
Additional information