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Proof step 10 from proof pot-square-est-02 (previous step)

4 ^ i1 * 4 ≤ (2 + i1) * (2 + i1), 0 ≤ i1, (i1 + 1) * (i1 + 1) < 4 ^ i1, 1 < i1, 0 < i1, ∀ i0. i→n(i0) < i→n(i1 + 1) → 4 ^ i0 ≤ (i0 + 1) * (i0 + 1) ∧ 0 < i0 ∧ 1 < i0 → false ⊦

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: (i1 + 1) * (i1 + 1) * 4 < 4 ^ i1 * 4

Additional information

Used simplifier rules: ls-pos: ⊦ 0 < i → (i * j < i * j0 ↔ j < j0); from specification int-mult%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs%lels-03: ⊦ i < j → (¬ ¬ j ≤ i ↔ false); from specification int-abs%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult Used formulas: (i1 + 1) * (i1 + 1) * 4 < 4 ^ i1 * 4