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Proof step 2 from proof pot-square-est-02 (previous step)

4 ^ i ≤ (i + 1) * (i + 1), 0 < i, 1 < i ⊦

User applied rule induction

And obtained the following new goals

Proof step 3:
4 ^ i ≤ (i + 1) * (i + 1) ∧ 0 < i ∧ 1 < i, ∀ i0. i→n(i0) < i→n(i) → 4 ^ i0 ≤ (i0 + 1) * (i0 + 1) ∧ 0 < i0 ∧ 1 < i0 → false ⊦ false

Rule argument

indvar: i→n(i) wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: i→n(i)