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Proof step 10 from proof pot-sub-dist (previous step)

i ^ j0 = 0, 0 ≤ i0, 0 ≤ i0 + j0, 0 ≤ j0 ⊦ i = 0, i ^ i0 = 0 / 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ 0 < j → (i ^ j = 0 ↔ i = 0)

Rule argument

spec: int-pot inst: name: zero seq: ⊦ 0 < j → (i ^ j = 0 ↔ i = 0) subst: [j, i] → [j0, i] flags: rewrite, current

Additional information

Used simplifier rules: Pot-zero: ⊦ j ^ 0 = 1;%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs%anti: ⊦ i ≤ j → (j ≤ i ↔ i = j); from specification int-abs Used terms: j0, i