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Proof step 2 from proof pot-sub-dist (previous step)

j0 ≤ j, 0 ≤ j0, 0 ≤ j ⊦ i ^ (j - j0) = i ^ j / i ^ j0, i = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
j = i0 + j0, j0 ≤ j, 0 ≤ j0, 0 ≤ j ⊦ i ^ i0 = i ^ j / i ^ j0, i = 0

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j, j0, i0] flags:

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j, j0, i0