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Proof step 4 from proof square-nls (previous step)

sqrt(j) < i, i ^ 2 ≤ j ⊦ i ^ 2 = i ^2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ i ^2 = i * i

Rule argument

spec: int-square inst: name: Square-def seq: ⊦ i ^2 = i * i subst: [i] → [i] flags: rewrite

Additional information

Used simplifier rules: pot-square-05: ⊦ i ^ 2 ≠ i * i ↔ false;%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult Used terms: i