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Proof step 1 from proof two-le (conclusion)

⊦ 0 ≤ i → (2 ^ i ≤ 2 ^ j ↔ i ≤ j)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: le-pos: ⊦ 1 < i ∧ 0 ≤ j → (i ^ j ≤ i ^ j0 ↔ j ≤ j0);