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Proof step 3 from proof zero (previous step)

i ^ j = 0, 0 < j, ∀ j0, i. i→n(j0) < i→n(j) → true → 0 < j0 → (i ^ j0 = 0 ↔ i = 0) ⊦ i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ 0 < i → j ^ i = j ^ i -1 * j
Proof step 5:
0 < j, i ^ j -1 * i = 0, 0 < j, ∀ j0, i. i→n(j0) < i→n(j) → true → 0 < j0 → (i ^ j0 = 0 ↔ i = 0) ⊦ i = 0

Rule argument

spec: int-pot inst: name: Pot-pos seq: ⊦ 0 < i → j ^ i = j ^ i -1 * j subst: [i, j] → [j, i] flags: rewrite, current

Additional information

Used terms: j, i