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Proof step 19 from proof euler-four-square-identity2 (previous step)

⊦ i2 ^2 * j4 ^2 + 2 * (i1 * j3) * i2 * j4 + i1 ^2 * j3 ^2 + 2 * (i3 * j1) * i4 * j2 + i4 ^2 * j2 ^2 + i4 ^2 * j4 ^2 + 2 * (i3 * j3) * i4 * j4 + i3 ^2 * j3 ^2 + 2 * (i2 * j2) * (i3 * j3 + i4 * j4) + i2 ^2 * j2 ^2 + 2 * ((i1 * j1) * i2 * j2 + (i1 * j1) * (i3 * j3 + i4 * j4)) + i3 ^2 * j4 ^2 + 2 * (i2 * j1) * i3 * j4 + i4 ^2 * j3 ^2 + 2 * (i4 * j3) * i1 * j2 + i1 ^2 * j2 ^2 + 2 * (i2 * j3) * i4 * j1 + i2 ^2 * j3 ^2 + i3 ^2 * j2 ^2 + 2 * (i3 * j2) * i1 * j4 + i1 ^2 * j4 ^2 = ((i1 ^2 * j2 ^2 + (i2 ^2 + i3 ^2 + i4 ^2) * j2 ^2) + (i1 ^2 + i2 ^2 + i3 ^2 + i4 ^2) * (j3 ^2 + j4 ^2)) + 2 * (i3 * j2 + i1 * j4) * (i2 * j3 + i4 * j1) + 2 * (i1 * j3 + i2 * j4) * (i3 * j1 + i4 * j2) + 2 * (i4 * j3 + i1 * j2) * (i2 * j1 + i3 * j4)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-in: ⊦ i + j = i + i0 ↔ j = i0; from specification int-basic2