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Proof step 15 from proof sqrt-mult-squares (previous step)

⊦ abs(j) * abs(j0) = abs(j) * sqrt(j0 * j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: abs-07: ⊦ abs(i) = 0 ↔ i = 0; from specification int-abs%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%neq-not-zero: ⊦ i * j ≠ i * j0 → i ≠ 0; (forward) from specification int-mult