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Proof step 4 from proof sqrt-mult-squares (
previous step
)
isSquare(i), ∃ j0. j0 * j0 = j ⊦ sqrt(i * j) = sqrt(i) * sqrt(j)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 5
:
isSquare(i) ⊦ sqrt(i * j0 * j0) = sqrt(i) * sqrt(j0 * j0)
Rule argument
Additional information