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Proof step 8 from proof sqrt-mult-squares (previous step)

⊦ sqrt((j * j) * j0 * j0) = sqrt(j * j) * sqrt(j0 * j0)

User applied rule cut formula

And obtained the following new goals

Proof step 9:
(j * j) * j0 * j0 = (j * j0) * j * j0 ⊦ sqrt((j * j) * j0 * j0) = sqrt(j * j) * sqrt(j0 * j0)

Rule argument

fma: (j * j) * j0 * j0 = (j * j0) * j * j0

Additional information

Used simplifier rules: associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult Used formulas: (j * j) * j0 * j0 = (j * j0) * j * j0