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Proof step 3 from proof square-le-one (previous step)

i < 4, 0 < i ⊦ sqrt(i) ≤ 1 ↔ i < 4

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i < 4, 0 < i, 0 < sqrt(i), 1 < sqrt(i) ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs%numlelsdel: j0 ≠ 0, j ≤ j0 ⊦ i < (* j) → i < (* j0); from specification int-abs