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Proof step 9 from proof square-nls (previous step)

sqrt(j) < i, i ^2 ≤ j, 0 ≤ j → sqrt(j) ^2 ≤ j ∧ j < (sqrt(j) + 1)^2 ⊦ 0 ≤ j

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: two-not-neg: ⊦ ¬ i ^2 < 0;%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs