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Proof step 36 from proof two-even (previous step)

2 * i = j1 ^2 + j2 ^2, j1 + j2 = j * 2 ⊦ (j1 - j2) % 2 = 0, i = ((j1 - j2) / 2)^2 + j ^2

User applied rule cut formula

And obtained the following new goals

Proof step 37:
j1 = j * 2 - j2, 2 * i = j1 ^2 + j2 ^2, j1 + j2 = j * 2 ⊦ (j1 - j2) % 2 = 0, i = ((j1 - j2) / 2)^2 + j ^2

Rule argument

fma: j1 = j * 2 - j2

Additional information

Used simplifier rules: sub-eq: ⊦ i - j = i0 ↔ i = i0 + j; from specification int-abs Used formulas: j1 = j * 2 - j2