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Proof step 53 from proof two-even (previous step)

2 * i = 2 * j2 ^2 + (2 * i1 + 1)^2 + 2 * (2 * i1 + 1) * j2 ⊦ i = ((2 * i1 + 1) / 2)^2 + ((2 * j2 + 2 * i1 + 1) / 2)^2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 54:
⊦ (i + j)^2 = i ^2 + 2 * i * j + j ^2
Proof step 55:
2 * i = 2 * j2 ^2 + ((2 * i1)^2 + 2 * (2 * i1) * 1 + 1 ^2) + 2 * (2 * i1 + 1) * j2 ⊦ i = ((2 * i1 + 1) / 2)^2 + ((2 * j2 + 2 * i1 + 1) / 2)^2

Rule argument

spec: inst: name: two-plus seq: ⊦ (i + j)^2 = i ^2 + 2 * i * j + j ^2 subst: [j, i] → [1, 2 * i1] flags: rewrite, current

Additional information

Used terms: 1, 2 * i1