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Proof step 58 from proof two-even (previous step)

2 * i = 2 * j2 ^2 + (2 * i1)^2 + 4 * i1 + 1 + 2 * (2 * i1 + 1) * j2 ⊦ i = ((2 * i1 + 1) / 2)^2 + ((2 * j2 + 2 * i1 + 1) / 2)^2

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: 2 * j2 ^2 + (2 * i1)^2 + 4 * i1 + 1 + 2 * (2 * i1 + 1) * j2 = 2 * (j2 ^2 + 2 * i1 ^2 + 2 * i1 + (2 * i1 + 1) * j2) + 1

Additional information

Used formulas: 2 * j2 ^2 + (2 * i1)^2 + 4 * i1 + 1 + 2 * (2 * i1 + 1) * j2 = 2 * (j2 ^2 + 2 * i1 ^2 + 2 * i1 + (2 * i1 + 1) * j2) + 1