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Proof step 9 from proof two-le-two (previous step)

1 < i * i, 0 < i * i, 2 < i * i, abs(i) ≤ 1, abs(i) < i * i ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ i ≠ 0 ∧ i ≠ 1 → (abs(i) ≤ 1 ↔ i = ~1)

Rule argument

spec: int-abs inst: name: abs-one-01 seq: ⊦ i ≠ 0 ∧ i ≠ 1 → (abs(i) ≤ 1 ↔ i = ~1) subst: [i] → [i] flags: rewrite

Additional information

Used simplifier rules: associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult Used terms: i