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Proof step 2 from proof two-ls-pospos (previous step)

0 ≤ i, 0 ≤ j ⊦ i ^2 < j ^2 ↔ i < j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i ^2 = i * i
Proof step 4:
0 ≤ i, 0 ≤ j ⊦ i * i < j ^2 ↔ i < j

Rule argument

spec: inst: name: Square-def seq: ⊦ i ^2 = i * i subst: [i] → [i] flags: rewrite, current

Additional information

Used terms: i