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Proof step 1 from proof two-mult (conclusion)

⊦ (i * j)^2 = i ^2 * j ^2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ i ^2 = i * i
Proof step 3:
⊦ (i * j) * i * j = i ^2 * j ^2

Rule argument

spec: int-square inst: name: Square-def seq: ⊦ i ^2 = i * i subst: [i] → [i * j] flags: rewrite, current

Additional information

Used terms: i * j