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Proof step 1 from proof two-plus (conclusion)
⊦ (i + j)^2 = i ^2 + 2 * i * j + j ^2
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 2
:
⊦ i ^2 = i * i
Proof step 3
:
⊦ (i + j) * (i + j) = i ^2 + 2 * i * j + j ^2
Rule argument
spec: int-square inst: name: Square-def seq: ⊦ i ^2 = i * i subst: [i] → [i + j] flags: rewrite, current
Additional information
Used terms: i + j