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Proof step 7 from proof abs-pred (previous step)

i - 1 < 0, i→n(~(i - 1)) < i→n(i), i < 0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
i < 0, i→n(1 - i) < i→n(i) ⊦

Rule argument

Additional information

Used simplifier rules: neg-15: ⊦ i + ~ j = i - j; from specification int-abs%minus-02: ⊦ ~(i - 1) = ~ i + 1; from specification int-abs%zero-gels-03: ⊦ i < 0 ∧ 0 ≤ j → i ≤ j; from specification int-abs%lsone: ⊦ i < 1 ↔ i ≤ 0; from specification int-abs%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%sub-ls: ⊦ i - j < i0 ↔ i < j + i0; from specification int-abs