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Proof step 12 from proof i2n-divtwo (previous step)

n→i(m0) + i = 0, i < 0 ⊦ m0 = i→n(i)

User applied rule cut formula

And closed the goal!

Rule argument

fma: i = ~ n→i(m0)

Additional information

Used simplifier rules: abs-neg: ⊦ i→n(~ i) = i→n(i);%n2n: ⊦ i→n(n→i(n)) = n;%negeq: ⊦ ~ i = j ↔ i + j = 0; from specification int-abs%neg-03: ⊦ ~ i + i = 0; from specification int-abs%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used formulas: i = ~ n→i(m0)