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Proof step 6 from proof i2n-mod (previous step)

0 ≤ i0 * j ∧ 0 ≤ j0, j0 < j, 0 < j, 0 ≤ j0, 0 ≤ i0 ⊦ i→n(j0) = (i→n(i0 * j) + i→n(j0)) % i→n(j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%zero-gels-04: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; from specification int-abs%zero-ge: ⊦ 0 < i → (0 ≤ i * j ↔ 0 ≤ j); from specification int-mult