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Proof step 14 from proof i2n (previous step)

0 ≤ i, 0 ≤ j ⊦ i→n(i) * i→n(j) = i→n(i * j)

User applied rule insert lemma

And obtained the following new goals

Rule argument

spec: intnat inst: name: i2np seq: 0 ≤ i, 0 ≤ j ⊦ i→n(i) * i→n(j) = i→n(i * j) subst: [i, j] → [i, j] flags: current, []

Additional information

Used terms: i, j