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Proof step 1 from proof inni-le-01 (conclusion)

⊦ n→i(m) + n→i(n) ≤ j → ¬ i→n(j) < m + n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i→n(j) < m + n, n→i(m) + n→i(n) ≤ j ⊦ m + n = 0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1