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Proof step 2 from proof inni-le (previous step)

n→i(n) < i, i→n(i) ≤ n, 0 < i ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i→n(i) ≤ n ↔ abs(i) ≤ n→i(n)

Rule argument

spec: intnat inst: name: switch-le seq: ⊦ i→n(i) ≤ n ↔ abs(i) ≤ n→i(n) subst: [n, i] → [n, i] flags: rewrite, current

Additional information

Used simplifier rules: abs-16: ⊦ 0 < j → abs(j) = j; from specification int-abs%lels-03: ⊦ i < j → (¬ ¬ j ≤ i ↔ false); from specification int-abs Used terms: n, i