[Imprint]
[Data Privacy Statement]
[E-Mail]
View
long theorem info
. View
the proof
. Back to
main index
. View
the specification
. View
theorem base summary
, View
theorem base listing
, the
used properties by spec
, the
dependency list
, the
symbol table
,
Proof step 3 from proof minus-one (
previous step
)
i + 1 < 0, n→i(m) = i + 1, i < 0 ⊦ m = 0 ∧ i = ~1
User applied rule insert equation
And closed the goal!
Rule argument
pos: left 2 flags: rotate, discard
Additional information
Used simplifier rules: nat2int-08: ⊦ ¬ n→i(n) < 0;