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Proof step 1 from proof mone (conclusion)

⊦ i→n(~1) = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ i < 0 → i→n(i) = i→n(~ i)

Rule argument

spec: intnat inst: name: Int2nat-neg seq: ⊦ i < 0 → i→n(i) = i→n(~ i) subst: [i] → [~1] flags: rewrite, current

Additional information

Used terms: ~1